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DVenus
a fost răspuns

([tex] \sqrt{5} [/tex]-[tex] \sqrt{2} [/tex])x-4=x([tex] \sqrt{5} [/tex]+[tex] \sqrt{2} [/tex])-7[tex] \sqrt{2} [/tex]

Răspuns :

⇒√5x-√2x-4=√5x+√2x-7√2
√5x-5x√-√2x-√2x=4-7√2
-2√2x=4-7√2                     ·(-1)
x=(7√2-4)/2√2   rationalizam
x=(7√2-4)(2√2)/2√2·2√2
x=(28-8√2)/8
x=4(7-4√2)/8
x=(7-4√2)2