Răspuns :
k=2N/m
/_\ L =40 cm => 0.4m
F•e(indice)=???
Fe=k × /_\L =>2N/m × 0.4 m= 0.8 N
=>Fe = 0.8 N
/_\ L =40 cm => 0.4m
F•e(indice)=???
Fe=k × /_\L =>2N/m × 0.4 m= 0.8 N
=>Fe = 0.8 N
K=2 N/m
deformarea=40 cm=0,40 m
F=?
F=K*deformarea=2 N/m * 0,40 m=0,8 N
deformarea=40 cm=0,40 m
F=?
F=K*deformarea=2 N/m * 0,40 m=0,8 N