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Rezolvati urmatoarele ecuatii: a) 13,2-x = 0,65 b) x ori 3 =-6 c) (-8) :t =-4 d) x:1,1 = 3 e) 5-2x=8 f) 2x+7= x-2 g) 3(t+1)-2 = 16 h) 4x-(1+3x )=-9 i) 11-3x (x-2)=14 j) x radical 2 = 12 k) x supra 2 minus 1 egal cu x l) |t| = 5

Răspuns :

Lipoc
a) 13,2-x=0,65=>-x=0,65-13,2=-12,55 b)x ori3=-6=>x=-6/4=-2 c)(-8):t=-4=>t=-4x8=-32 d)x:1,1=3=>x=3x1,1=3,3 e)5-2x=8=>-2x=8-5=>-2x=3=>x=3/-3 f)2x+7=x-2=>2x-x=2-7=>x=-9 g)3t+3-2=16=>3t+1=16=>3t=15=>t=5 h)4x-(1+3x)=-9=>4x-1-3x=-8=>-x=-8=>x=8 i) 11-3x(x-2)=14=>11-3xpatrat +6x=14=>-3patrat+6x+11-14=0=>-3xpatrat+6-3=0=> delta=36-36=0=>x1=x2=1 k)x/2-1=x aduci la acelasi numitor cu 2=>x-2=2x=>x-2x=2=>-x=2=>x=-2