7^2:{17^2:289+2×[(2^3×3)^15:(2×2^43×3^15)+1^100]}=
=7^2:{288:288+2×[(8×3)^15:(2^44×3^15)+1]}=
=49:{1+2×[24^15:(2^44×3^15)+1]}=
=49:{1+2×[24^15: Nu stiu calcula din paranteza caci e 2 si 3 daca ar fi 2si 2 sau 3si 3 la puterea a44 respectiv15 atunci as sti face
