[tex]\it \dfrac{x}{y}=\dfrac{3}{5} \Rightarrow \dfrac{x}{y}=0,6 \Rightarrow x=0,6y\ \ \ \ \ (*)\\ \\ \\ \dfrac{2x+3y}{5x-2y}\ \stackrel{(*)}{=}\ \dfrac{2\cdot0,6y+3y}{5\cdot0,6y-2y}=\dfrac{4,2y}{y}=4,2=\dfrac{\ \ 42^{(2}}{10}=\dfrac{21}{5}[/tex]
