Răspuns :
b)
[tex]\it |x+1|+|2x+2|+|3x+3|=6 \Rightarrow |x+1|+2|x+1|+3|x+1|=6 \Rightarrow \\ \\ \Rightarrow |x+1|(1+2+3)=6 \Rightarrow |x=1|\cdot6=6\Big|_{:6} \Rightarrow |x+1|=1 \Rightarrow x+1=\pm1 \Rightarrow \\ \\ x+1\in\{-1,\ \ 1\}\Big|_{-1} \Rightarrow x\in\{-2,\ \ 0\}[/tex]