[tex]\displaystyle\\\frac{x}{y}=\frac{2}{3} \implies 3x = 2y \implies y = \frac{3x}{2} \\ \\ \\\frac{3x-1}{x+y}= \frac{3x - 1 }{x + \frac{3x}{2}} = \frac{3x-1}{\frac{5x}{2}} \\ \\ \\= \frac{3x-1}{1} \cdot \frac{2}{5x} = \frac{6x-2}{5x}[/tex]
