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Andreutzakriss
a fost răspuns

[tex]\sqrt{ \frac{x^2}{25} }- \sqrt{ \frac{y^2}{16} }=[/tex]

Răspuns :

Alexandraa2
[tex] \frac{ \sqrt{ x^{2} } }{5} - \frac{ \sqrt{ y^{2} } }{4} = \frac{x}{5} - \frac{y}{4} = \frac{4x-5y}{20} [/tex]
   
[tex]\displaystyle \sqrt{ \frac{x^2}{25} }- \sqrt{ \frac{y^2}{16} }= \frac{x}{5}- \frac{y}{4} = \boxed{\frac{4x-5y}{20} } [/tex]