Răspuns:
MNa2CO3=2×23+12+3×16=106g/mol
MHCl=1+35,5=36,5g/mol
MCO2 =12+2×16=44g/mol
106g.................2x36,5g.........................................44g
Na 2 CO 3 + 2 HCl → 2 NaCI + H 2 O + CO 2
xg........................3,65g...........................................yg
x=3,65×106/2×36,5=calculează
y= 44x3,65/2×36,5= calculează