Răspuns:
Ca = 40 g/mol
O = 16 g/mol
H = 1 g/mol
Mg = 24 g/mol
C = 12g/mol
a) 40 g/mol + 2× 16 g/mol + 2× 1 g/mol = 40 g/mol + 32 g/mol + 2 g/mol = 74 g/mol
2 moli de hidroxid de calciu = 2 × 74g = 148 g (pe 2 moli)
b) 24 g/mol + 12 g/mol + 3× 16g/mol = 84 g/mol
4 moli de carbonat de magneziu = 4 × 84g = 336g (pe 4 moli)
Explicație:
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