Răspuns:
Explicație pas cu pas:
[tex]\bf a)~~2^{10} \cdot 32=2^{10} \cdot 2^{5}=2^{10+5}=\red{2^{15}}[/tex]
[tex]\bf b)~~81 \cdot 3^{7} \cdot 3^{8}=3^{4}\cdot 3^{7} \cdot 3^{8}=3^{4+7+8}=\purple{3^{19}}[/tex]
[tex]\bf c)~~ 2^{17} \cdot 4^{5}=2^{17}\cdot \Big(2^{2} \Big)^{5}= 2^{17}\cdot 2^{2\cdot5} =2^{17+10}=\pink{2^{27}}[/tex]
