Răspuns :
3a+12b=66
3a=66-12b
3a=2(33-6b) (numar par)
3a=impar
Rezulta ca 2 numar prim par=2
6+12b=66
12b=66-6
12b=60
b=60:12
b=5
[tex]\it 3a+12b=66|_{:3} \Rightarrow a+4b=22\ \ \ \ \ (1)\\ \\ (1) \Rightarrow a=par\ \ \ \ (2)\\ \\ Dar,\ a=prim\ \ \ (3)\\ \\ (2),\ (3) \Rightarrow a=2 \ (singurul\ nr.\ prim,\ care\ este\ par)\\ \\ a=2\ \stackrel{(1)}{\Longrightarrow}\ 2+4b=22|_{-2} \Rightarrow 4b=20 \Rightarrow b=5[/tex]
Numerele cerute sunt: a=2, b=5