👤
Cry2oo7
a fost răspuns

efectueaza folosind factorul comun(a+b)×(b+c)×(c+a)-(a+b)×(b-c)×(a+c)​

Răspuns :

Dianageorgiana794

Răspuns:

(a+b)·(b+c)·(c+a) - (a+b)·(b-c)·(a+c)​=

(a+b)(a+c)[(b+c)-(b-c)]=

(a+b)(a+c)(b+c-b+c)=

(a+b)(a+c)·2c

Targoviste44

[tex]\it (a+b) \cdot (b+c) \cdot (c+a)\ -\ (a+b) \cdot (b-c) \cdot (a+c)=(a+b)(a+c)(b+c-b+c)=\\ \\ =(a+b)(a+c)\cdot2c=2c(a+b)(a+c)[/tex]