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a fost răspuns

determinați numarul n pentru care {[(4+4)×4-4+4×(4+4:4)]:4+4×4-4:4×4}× n+5=2021​

Răspuns :

Jojoi54

{[(4+4)×4-4+4×(4+4:4)]:4+4×4-4:4×4}× n+5=2021

{[8x4-4+4x(4+1)]:4+16-1x4}x n+5=2021

[(32-4+4x5):4+16-4]x n+5=2021

[(32-4+20):4+16-4]x n+5=2021

[(28+20):4+16-4]x n+5=2021

(48:4+16-4)x n+5=2021

(12+12)x n+5=2021

24x n+5=2021

24xn=2021-5

24x n=2016

n=2016:24

n=84

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