Răspuns :
(x+1)(2x+4)=0 => x+1=0
[tex] x_{1} [/tex]=-1
2x+4=0
2x=-4 | :2
[tex] x_{2} [/tex]=-2
:)
[tex] x_{1} [/tex]=-1
2x+4=0
2x=-4 | :2
[tex] x_{2} [/tex]=-2
:)