Răspuns :
[tex]ab+ac+ad=2005\\\\a\cdot(b+c+d)=2005\\\\401\cdot a=2005\\\\a=\boxed{\boxed{5}}[/tex]
Dai factor comun pe a:
ab+ac+ad = a*(b+c+d)
=> a=2005/(b+c+d)
a=2005/401
a=5
:D
ab+ac+ad = a*(b+c+d)
=> a=2005/(b+c+d)
a=2005/401
a=5
:D