Explicatie pas cu pas:
[tex]$\mathbf{4. \: {9}^{12} \times {9}^{15} \div (9 {}^{3}) {}^{9} }$[/tex]
[tex]$\mathbf{ {9}^{12} \times {9}^{15} \div {9}^{3 \times 9} = 9 {}^{12} \times {9}^{15} \div {9}^{27} }$[/tex]
[tex]$\mathbf{ {9}^{12 + 15 - 27} = 9 {}^{0} = \:\boxed{\mathbf{1}}}$[/tex]
[tex]\mathbf{5. \: {19}^{0} + {1}^{53} + {2}^{3} + 0 {}^{1000} }[/tex]
[tex]\mathbf{1 + 1 + 8 + 0 = 2 + 8 = \boxed{\mathbf{10}} }[/tex]
6. Primul pas e sa transformam pe 9^5 sub forma cu baza 3
[tex] \mathbf{9 {}^{5} = (3 {}^{2} ) {}^{5} = 3 {}^{2 \times 5} = 3 {}^{10} }[/tex]
[tex] \mathbf{3 {}^{10} < 3 {}^{27} \:\longmapsto \:\boxed{\mathbf{9 {}^{10} < 3 {}^{27} }} }[/tex]
Bafta ! :)
