Răspuns:
Explicație pas cu pas:
a) x³+x²-x-1 = (x³-x) + (x²-1) = x(x²-1) + (x²-1) = (x²-1)(x+1) =
= (x-1)(x+1)(x+1) = (x-1)(x+1)²
d) x³+x²-25x-25 = x²(x+1) - 25(x+1) = (x+1)(x²-25) =
= (x+1)(x-5)(x+5)
g) 4x³-12x²-x+3 = 4x²(x-3)-(x-3) = (x-3)(4x²-1) =
= (x-3)(2x-1)(2x+1)
j) 9x³+27x²-4x-12 = 9x²(x+3)-4(x+3) = (x+3)(9x²-4) =
=(x+3)(3x-2)(3x+2)
g') 4x-12x-x+3 = -9x+3 = (-3)(3x-1)
