👤
DVenus
a fost răspuns

0,(1)[tex] x^{2} [/tex]-0,25=([tex] \frac{x}{3} [/tex]-2)[tex] ^{2} [/tex]

Răspuns :

Daca paranteza din dreapta este inmultita cu 2, ecuatia nu are solutii, asa ca cred ca ecuatia este asa:

[tex]\dfrac{x^2}{9}-\dfrac14=(\dfrac x3-2)^2[/tex]

[tex]\dfrac{x^2}{9}-\dfrac14=\dfrac{x^2}{9}-\dfrac{4x}{3}+4[/tex]

[tex]\dfrac{4x}{3}=4+\dfrac14[/tex]

[tex]\dfrac{4x}{3}=\dfrac{17}{4}[/tex]

[tex]x=\dfrac{3\cdot17}{16}=\dfrac{51}{16}=3\dfrac{3}{16}[/tex]

Alte intrebari