Răspuns :
1)Se face asa: Notam cu x pestii mari.Pestii mari vor manca x*3 pesti mici .In total avem : x+x*3=20 , x*( 1+3)=20 , x*4 =20 ,x=20:4 , x=5 pesti mari , pesti mici = 5*3=15iti raman pestii mari,adica 5 2) a=/---/
b=/---/+2
c=/---/---/---/---/---/
d=/---/ c+d=360
e=/---/---/---/---/
f=/---/ e-f=321
calculam mai intai c,d,
360:6=60 -->d=60.
60x5=300 --> c=300
calculam e si f
321:3=107 --> f=107
107x4=428 -->e=428
adunam c,d,e,f 300+60+428+107=895.
scoatem din suma totala 1433-895=538.
acum putem calcula pe a si b.
(538-2):2=536:2=268 --> a=268 atunci b=268+2=270
Verificare a+b+c+d+e+f=268+270+300+60+428+107=1433 3)100-20=80 80ghiocei si 20 viorele 123-30=93 93viorele si 30 margaritar
28 zile februarie=28 ghiocei
108 ghiocei+113 viorele +x+30 margaritar=300
221+x+30=300
x+30=79margaritar
108 ghiocei 113 viorele 79 margaritar.
b=/---/+2
c=/---/---/---/---/---/
d=/---/ c+d=360
e=/---/---/---/---/
f=/---/ e-f=321
calculam mai intai c,d,
360:6=60 -->d=60.
60x5=300 --> c=300
calculam e si f
321:3=107 --> f=107
107x4=428 -->e=428
adunam c,d,e,f 300+60+428+107=895.
scoatem din suma totala 1433-895=538.
acum putem calcula pe a si b.
(538-2):2=536:2=268 --> a=268 atunci b=268+2=270
Verificare a+b+c+d+e+f=268+270+300+60+428+107=1433 3)100-20=80 80ghiocei si 20 viorele 123-30=93 93viorele si 30 margaritar
28 zile februarie=28 ghiocei
108 ghiocei+113 viorele +x+30 margaritar=300
221+x+30=300
x+30=79margaritar
108 ghiocei 113 viorele 79 margaritar.