Răspuns :
X-traseul ce trebuie parcurs
I zi : 2/6·x=2x/6 simplificam cu 2=x/3
II zi: 1/4(x-x/3)=1/4·2x/3=2x/12 simplificam cu 2=x/6
III zi: 12 km
x=x/3+x/6+12
x-x/3-x/6=12 aducem la acelasi numitor
(6x-2x-x)/6=12
3x/6=12
3x=6·12
x=72/3
x=24 km
trebuia parcurs un traseu de 24 km
verificare
I zi : 2/6·24=2·24/6=8 km
II zi: 1/4 din traseul ramas adica 24-8=16 deci 1/4 din 16km
16/4= 4 km
III zi: 12 km
8+4+12=24 km
I zi : 2/6·x=2x/6 simplificam cu 2=x/3
II zi: 1/4(x-x/3)=1/4·2x/3=2x/12 simplificam cu 2=x/6
III zi: 12 km
x=x/3+x/6+12
x-x/3-x/6=12 aducem la acelasi numitor
(6x-2x-x)/6=12
3x/6=12
3x=6·12
x=72/3
x=24 km
trebuia parcurs un traseu de 24 km
verificare
I zi : 2/6·24=2·24/6=8 km
II zi: 1/4 din traseul ramas adica 24-8=16 deci 1/4 din 16km
16/4= 4 km
III zi: 12 km
8+4+12=24 km
x-traseul
I [tex] \frac{2}{6}*x=\frac{1}{3}*x[/tex]
II [tex] \frac{1}{4}*(x- \frac{2}{6} x)= \frac{1}{4} * \frac{4}{6}x= \frac{1}{6}x [/tex]
III 12
[tex]b) x= \frac{1}{3} x+ \frac{1}{6}x+12=>x= \frac{3}{6} x+12=>x= \frac{1}{2} x+12=>x- \frac{1}{2}x=12 \\ => \frac{1}{2} x=12=>x=2*12=>x=24 [/tex]
[tex]c) \frac{1}{3} x= \frac{1}{3}*24=8 [/tex]
[tex]d) \frac{1}{6}*x= \frac{1}{6}*24=4 [/tex]
PROBA: 12+8+4=24 ADEVARAT
I [tex] \frac{2}{6}*x=\frac{1}{3}*x[/tex]
II [tex] \frac{1}{4}*(x- \frac{2}{6} x)= \frac{1}{4} * \frac{4}{6}x= \frac{1}{6}x [/tex]
III 12
[tex]b) x= \frac{1}{3} x+ \frac{1}{6}x+12=>x= \frac{3}{6} x+12=>x= \frac{1}{2} x+12=>x- \frac{1}{2}x=12 \\ => \frac{1}{2} x=12=>x=2*12=>x=24 [/tex]
[tex]c) \frac{1}{3} x= \frac{1}{3}*24=8 [/tex]
[tex]d) \frac{1}{6}*x= \frac{1}{6}*24=4 [/tex]
PROBA: 12+8+4=24 ADEVARAT