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Fie triunghiul dreptunghic ABC m(A)=90, AB=15 cm, AD= 12 cm, D∈(BC). Aflati: BC, Ac, sin C, cos C, tg B, ctg B.

Răspuns :

Meryistrate
inΔADB-drept.   cuD=90 gr.
BD²=AB²-AD²
BD=√225-144
BD=√81
BD=9 cm
teorema inaltimi
AD²=CD*BD
144=CD*9
CD=144:9
cd=16
BC=16+9=25
inΔADC drept. cu D=90 gr.
AC²=AD²+CD²
AC=√144+256
AC=√400
AC=20
sinC=AB/BC
sinC=15/25=3/5
cosC=AC/BC=20/25=4/5
tgB=AC/AB=20/15=4/3
ctgB=AB/AC=15/20=3/4

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