a=
[tex] \sqrt{2} \times ( \frac{1}{ \sqrt{2} }+ rad.2 ) + 2[/tex]
b=
[tex] \sqrt{3} \times ( \frac{4}{ \sqrt{3} } - \sqrt{3} ) + 4[/tex]
a=
[tex] \sqrt{2} \times \frac{3 \sqrt{2} }{2} + 2[/tex]
a=
[tex] \frac{6}{2} + 2 = 3 + 2 = 5[/tex]
a=5
b=
[tex] \sqrt{3} \times \frac{ \sqrt{3} }{3} + 4 = \frac{3}{3} + 4 = 1 + 4 = 5 [/tex]
b=a=5
