Răspuns:
Explicație pas cu pas:
[tex]=\dfrac{(\sqrt{3})^{2} }{6^{2}}*(\dfrac{10}{\sqrt{25*3} }+\dfrac{\sqrt{25*2} }{\sqrt{9^{2}*6} } )*\dfrac{9\sqrt{3} }{23}=\dfrac{1}{12}*(\dfrac{10}{5\sqrt{3} }+\dfrac{5\sqrt{2} }{9\sqrt{6} })*\dfrac{9\sqrt{3} }{23}=\dfrac{1}{12}*( \dfrac{2}{\sqrt{3} }+\dfrac{5}{9\sqrt{3} })*\dfrac{9\sqrt{3} }{23}=\dfrac{1}{12}*\dfrac{18+5}{9\sqrt{3} }* \dfrac{9\sqrt{3} }{23}=\dfrac{1}{12}[/tex]
