Răspuns:
Explicație:
ms1=150g sol. NaOH
c1=16%
ms2=160g sol. NaOH
c2=10%
cf
-se afla md1 din prima sol.de NaOH
md1= c1 .ms1 : 100
md1=150 . 16: 100= 24g NaOH
-se afla md2
md2= 10 .160 : 100=16g NaOH
-se afla md final
md f= 24 + 16 =40g NaOH
-se afla ms final
ms f=150 + 160=310 g sol. NaOH
-se afla cfinal
cf= mdf . 100 : msf
cf= 40.100 : 310=12,9 %
-se foloseste relatia : cm= c . 10 . ro : M
cm=12,9 . 10 . 1,137 : 40=3,67
MNaOH=23 + 16 +1=40------> 40g/moli
