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a fost răspuns

a) 2+4+6+.....+2018+1010
b)1+3+5+.......+2019??????

Răspuns :

Bsorin578

2+4+6+...+2018+1010=

Scoatem 2 factor comun

=2(1+2+3+...+1009)+1010=

=2 x 1009x1010/2 +1010=

= 1009x1010 +1010=

=1010(1009+1)=

=1010 x 1010

= [tex]1010^{2}[/tex]

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