Va rog sa ma ajutati la a si la b!
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[tex]arcsin \frac{1}{2} + arccos \frac{ \sqrt{3} }{2} = \frac{\pi}{6} + \frac{\pi}{6} = \frac{2\pi}{6} = \frac{\pi}{3} \\ arcsin( - \frac{ \sqrt{3} }{2} ) + arsin1 = \frac{4\pi}{3} + \frac{\pi}{2} = \frac{12\pi}{6} = 2\pi[/tex]