5.
x/y=1,(3)
x/y=(13-1):9
x/y=12/9=4/3
x/y=4/3
x/4=y=3=k, unde k-apartine numerelor naturale
x=4k
y=3k
(2×4k-3k)/(3×4k+3k)=
=(8k-3k)/(12k+3k)=
=11k/15k=
=11/15.
6.
a/18=b/25=k, ca la problema 5. k-apartine numerelor naturale
a×p%=b ?
a=18k
b=25k
18k×p%=25k
p%=25k/18k
p%=25/18
p%=1,388.
(la aceasta problema nu sunt sigura :( ).
Sper ca te am ajutat!:)
