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Determinati numerele reale x si y stiind ca :
a) x²+6x+4y²-4y+10=0
B0.16x²+0.8x+y²-2y+2=0
Dau coroana, URGENT

Răspuns :

Dariuslacatusu5
a)x^2+2×3x+3^2+(2y)^2-2×2y×1+1=0
(x+3)^2+(2y-1)^2=0----->|x+3=0---->|x=-3
|2y-1=0---->|y=1/2

b)(0,4x)^2+2×0,4x×1+1^2+y^2-2×y×1+1^2=0
(0,4x+1)^2+(y-1)^2=0----->|0,4x+1=0---->0,4x=1-->
|y-1=0----->y=1
----->x=1/0,4=10/4=5/2
x=5/2
y=1





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