ΔCAB dr
m (∡CAB) = 30° => AB = 2BC = 2×10 =20 cm
ΔCAB -dr => AC² = 400 - 100 => AC = 10√3 cm
ΔDAC - dr
m (∡DCA) = 30° => AD = AC /2 =10√3 /2 = 5√3 cm
ΔDCA - dr => DC² = 300 - 75 => DC= √225 = 15 cm
Notam cu :
M mijl [AD]
N mijl [CD] } MN-lm in trapez => MN = (B+b) /2 =( AB+DC) / 2 = 20 + 15 / 2 = 35 /2 = 27,5 cm