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Cristisiacestmail
a fost răspuns

Aflati c m m m c al numerelor a. x=4•3^8+2•3^11 si y=9^5+27^3

Răspuns :

Ahmed1985

X= 3⁸×(4×1+2×27) =

X= 3⁸×(4+54) =

X= 3⁸×58 = 2×3⁸×29


Y= (3²)⁵ + (3³)³= 3¹⁰+3⁹

Y= 3⁹×(3+1) =

Y= 3⁹×4 = 3⁹×2²

Cmmmc = 2²×3⁹×29

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