a) Aria paralelogram =baza·inaltimea . In ABCD csd. AB=8cm baza si AE -inaltimea ( AE⊥DC din enunt)
=>Aria ABCD=AB·AE=8cm·AEcm=40cm².
b)Fie OM⊥AB, M∈AB.
Daca AC∩DB={O}, O-mijlocul AC si DB (in paralelogram diagonalele se injumatatesc)
ΔAOM asemenea ΔAEC ( ∡OAM=∡ACE- ca unghiuri alterne interne si ∡OMA=∡AEC=90°)
=>OM/AC=OB/AD=AM/EC
=> OM/5=AO/AC=1/2=> OM=5/2.
=> Aria AOB=AB·OM/2=(8·5/2)/2=20/2=10cm².