-calculez masa si moli acid din solutie
c=mdx100/ms---> md= 160x36,5/100g= 1,6x36,5gHCl
niu= m/M= 1,6X36,5g/36,5g/mol= 1,6molHCl
-din ecuatia chimica, deduc moli carbonat
1mol..................2mol
Na2CO3 + 2HCl----> 2NaCl + H2O+ CO2
x.....................1,6mol
x= 0,8mol Na2CO3
-calculez masa de carbonat, stiind M,Na2CO3= 106g/mol
m= niuxM= 0,8molx106g/mol= 84,8gNa2CO3
-calculez masa de solutie., stiind md= 84,8g
5,5= 84,8x100/ms..........................calculeaza ms !!!!!
