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Rezolvare a ecuatiilor : 5(x+2)+3(x+1)=27 , 7(x+2)+5(x+1)=39

Răspuns :

CosmoteRo

a).  5x+10+3x+3=27

8x+13=27

8x=27-13

8x=14

x=14/8=7/4 (s-a simplificat cu 2)

b). 7x+14+5x+5=39

12x+19=39

12x=39-19

12x=20

x=20/12=10/6=5/3

5(x + 2) + 3(x + 1) = 27

5x + 10 + 3x + 3 = 27

8x = 14 / : 2

4x = 7

x = 7/4


7(x + 2) + 5(x + 1) = 39

7x + 14 + 5x + 5 = 39

12x + 19 = 39

12x = 20 / : 4

3x = 5

x = 5/3

Alte intrebari