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Cum se procedeaza pentru a calcula urmatoarea:
[tex] \frac{1+ \sqrt{2}+ \sqrt{3}+ \sqrt{5}+ \sqrt{10} + \sqrt{15} }{1+ \sqrt{2}+ \sqrt{3} } [/tex]


Răspuns :

[tex] \frac{1+ \sqrt{2}+ \sqrt{3} + \sqrt{5}(1+ \sqrt{2} + \sqrt{3} ) }{1+ \sqrt{2}+ \sqrt{3} } = \frac{(1+ \sqrt{2}+ \sqrt{3})(1+ \sqrt{5)} }{1+ \sqrt{2}+ \sqrt{3} } =1+ \sqrt{5} [/tex]
sper ca te-am ajutat!

[tex] \frac{1+ \sqrt{2} + \sqrt{3}+ \sqrt{5} + \sqrt{10} + \sqrt{15} }{1+ \sqrt{2} + \sqrt{3} }= \\ = \frac{( 1+\sqrt{2} + \sqrt{3})+ \sqrt{5}( 1+\sqrt{2}+ \sqrt{3}) }{1+ \sqrt{2} + \sqrt{3} } = \\ = \frac{(1+ \sqrt{2} + \sqrt{3})(1+ \sqrt{5}) }{1+ \sqrt{2}+ \sqrt{3} } = \\ =1+ \sqrt{5} [/tex]