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Numelemeu
a fost răspuns

Daca a=[tex] \frac{5}{6}[/tex] , b+c=[tex] \frac{7}{20}[/tex] si c-d=[tex] \frac{1}{24}[/tex] , calculati a*b+2*a*c-a*d.

Răspuns :

Red12dog34
[tex]ab+2ac-ad=ab+ac+ac-ad=a(b+c)+a(c-d)=\\=\displaystyle\frac{5}{6}\cdot\frac{7}{20}+\frac{5}{6}\cdot\frac{1}{24}=\frac{7}{24}+\frac{5}{144}=\frac{47}{144}[/tex]
Miky93
ab +2ac-ad= ab+ac+ac-ad=a(b+c)+a(c-d)= 5/6 * 7/20 + 5/6 *1/24=7/24 + 5/144=

=(42+5)/144= 47/144

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