In primul rand,trebuie sa stii ca la impartirea putetilor,se scad exponentii(daca sunt aceeasi)
[tex]a^{m} \div a^{n} = a^{m - n} [/tex]
Acum....la exercitii:
a)
[tex]2 ^{49} \div 2 ^{13} = 2 ^{36} [/tex]
b)
[tex]3 ^{103} \div 3^{91} = 3^{12} [/tex]
c)
[tex]5 ^{96} \div 5^{96} = 5 ^{0} = 1 [/tex]
d)
[tex]3 ^{42} \div 3^{12} \div 3 = 3^{29} [/tex]
Deoarece,daca o o putere nu are exponent,atinci se deduce ca are exponentul 1.
e)
[tex]7 ^{49} \div 7 ^{15} \div 7 ^{9} = 7 ^{25} [/tex]
f)
[tex]7^ {32} \div 7^{5} = 7 ^{27} [/tex]
g)
[tex]5^{312} \div 5 ^{56} = 5^{256} [/tex]
h)
[tex]71^{32} \div 71^{5} = 71^{27} [/tex]
i)
[tex]6^{112} \div 6^{12} \div 6^{43} = 6^{57} [/tex]
j)
[tex]8^{91} \div 8^{75} \div 8^{10} = 8^{6} [/tex]
k)
[tex](5^{3})^{23} = 5^{69} [/tex]
Deoarece,la orice putere cara la exponent are inmultire,se efectueaza inmultirea la exponent.De exemplu:
[tex]a ^{x} \times a ^{z} = a ^{x \times z} [/tex]
l)
[tex](3^{7})^{21} = 3 ^{147} [/tex]
m)
[tex](25^{1})^{14} = 25^{14} \\ 1 \times 14 = 14[/tex]
n)
[tex]{(2^{5})^{4}}^{6} = 2^{120} [/tex]
o)
[tex]{(32^{14})^{5}}^{0} = 32^{0} = 1[/tex]
Sper ca te-am ajutat.
