Răspuns :
[tex]4 \sqrt{12} + 7 \sqrt{27} - 4 \sqrt{48} + \sqrt{192} - 2 \sqrt{363} = \\ \\ 4 \times 2 \sqrt{3} + 7 \times 3 \sqrt{3} - 4 \times 4 \sqrt{3} + 8 \sqrt{3} - 2 \times 11 \sqrt{3} = \\ \\ 8 \sqrt{3} + 21 \sqrt{3} - 16 \sqrt{3} + 8 \sqrt{3} - 22 \sqrt{3} = \\ \\ (8 + 21 - 16 + 8 - 22) \sqrt{3} = \\ \\ - 1 \sqrt{3} = \\ \\ - \sqrt{3} [/tex]