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Se stie ca a+b+c=23 si x=9. Calculati: 2013-( 53×a+53×b+53×c+10×c)! 424-21×x+3×a+3×b+3×c! 3147-10×x-( 100×a+100×b+100×c) .

Răspuns :

[tex]a + b + c = 23[/tex]

[tex]x = 9[/tex]

[tex]2013 - (53a + 53b + 53c + 10x)[/tex]

[tex] = 2013 - [53(a + b + c) + 10x][/tex]

[tex] = 2013 - (53 \times 23 + 10 \times 9)[/tex]

[tex] = 2013 - (1219 + 90)[/tex]

[tex] = 2013 - 1309[/tex]

[tex] = 704[/tex]

[tex]424 - 21x + 3a + 3b + 3c[/tex]

[tex] = 424 - 21x + 3(a + b + c)[/tex]

[tex] = 424 - 21 \times 9 + 3 \times 23[/tex]

[tex] = 424 - 189 + 69[/tex]

[tex] = 235 + 69[/tex]

[tex] = 304[/tex]

[tex]3147 - 10x - (100a + 100b + 100c)[/tex]

[tex] = 3147 - 10 x - 100(a + b + c)[/tex]

[tex] = 3147 - 10 \times 9 - 100 \times 23[/tex]

[tex] = 3147 - 90 - 2300[/tex]

[tex] = 3057 - 2300[/tex]

[tex] = 757[/tex]