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Frumi111
a fost răspuns

8 si 9 am nevoie urgent

8 Si 9 Am Nevoie Urgent class=

Răspuns :

Mikelina
8)46:2+84:4=22×2
9)Pabcd=2(AB+BC)
P=2(96+42)
P=2×138=276
Pefgh=2(EF+FG)
EB=96:3=32
EF=EB+BF
EF=2EB=2×32=64
BF=FG=EB
P=2(64+32)
P=2×96=192

CubotR9
8. 46:2= 23 ( jumatatea)
84:4=21( sfertul )
23+21=44

( 42:2)+( 84:4)= 23+21= 44

9. AB=96
BC=42

P= 2xL+2xl
P=2x96+2x42=192+84=
= 276

EB= AB:3
EB=BF

EB=AB:3= > 96:3= 32
EB=BF --> 32=32
EB = 4x32=128

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