evident ca solutia se dilueaza si va avea o conc. mai mica
c= mdx100/ms
calculez md1-,din prima solutie--->md1= 10x300/100= 30g sare
in a doua solutie, se modifica doar ms: ms2=ms1+m,apa= 400g iar md ramane acelasi--> md2=md1= 30g
c2= md2x100/ms2= 30x100/ 400=.........................calculeaza !!!!
