Răspuns :
=-125/x(x-5)+x²/(x-5)=
=(-125+x²·x)/x(x-5)=
=(-125+x³)/x(x-5)
=[(x+5)(x-5)(x+5)]/x(x-5)]=simplif cu x-5=
=(x+5)²/x
cond x≠0
(x+5)²=0
x₁=x₂=-5
=(-125+x²·x)/x(x-5)=
=(-125+x³)/x(x-5)
=[(x+5)(x-5)(x+5)]/x(x-5)]=simplif cu x-5=
=(x+5)²/x
cond x≠0
(x+5)²=0
x₁=x₂=-5