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care sunt nr de forma xyz stiind ca xy+yz+zx=66 -explicație pt. elev de clasa a IV-a

Răspuns :

 

[tex]\displaystyle\\

\text{Se cer numerele de forma }~\overline{xyz}~\text{ stiind ca } ~ \overline{xy}+\overline{yz}+\overline{zx}=66\\\\

\text{Rezolvare:}\\\\

\text{Descompunem in zeci si unitati numerele de 2 cifre.}\\\\

\overline{xy}+\overline{yz}+\overline{zx}=66\\\\

10x+y+10y+z+10z+x=66\\\\

10x+x+10y+y+10z+z=66\\\\

11x+11y+11z=66\\\\

11(x+y+z)=66\\\\

x+y+z = \frac{66}{11}\\\\

\boxed{\bf x+y+z=6}[/tex]

[tex]\Longrightarrow~~\text{Numerele de forma }~\overline{xyz}~\text{ au suma cifrelor egala cu 6.}\\\\

\Longrightarrow~~\overline{xyz}\in\{114;~123;~132;~141;~213;~222;~ 231;~312;~321;~411\}[/tex]