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Daria5002
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Chenarele albastre dau și coroana!Am nevoie de ele la școala !clasa a 7 a

Chenarele Albastre Dau Și CoroanaAm Nevoie De Ele La Școala Clasa A 7 A class=

Răspuns :

6adri6
1)a) MCaCO₃=40+12+48=100
1 mol CaCO₃=100 g

100 g CaCO₃......40gCa.....12gC.......48gO
100 g CaCO₃.........x..............y..............z

x=40%
y=12%
z=48%

b) MCaO=40+12=52
1 mol CaO=52 g
52g CaO.........40gCa.......12gO
100g CaO.........a................b

a=(40*100):52=76,92%Ca
b=(12*100):52=23,07%O

c)MCH₄=12+4=16
1 mol CH₄=16 g

16g CH₄........12gC...........4gH
100g CH₄.........s.................t

s=(12*100):16=75%C
t=(4*100):16=25%H

d)MMgCl₂=24+35,5*2=24+71=95
1 mol MgCl₂=95 g
95g MgCl₂.........24 g Mg.......71 g Cl
100 g MgCl₂..........q....................r

q=(24*100):95=25,26 % Mg
r=(71*100):95=74,73 % Cl

2)a)36g H₂O
MH₂O=2+16=18 g
18g H₂O..........16g O
36g H₂O.............x

x=(16*36):18=32 g O

b)2 moli H₂SO₄
MH₂SO₄=2+32+64=98
2 moli H₂SO₄=2*98=196 g

98 g H₂SO₄.........64 g O
196 g H₂SO₄..........a

a=(64*196):98=128 g O

c)0,15 kmoli SO₂
MSO₂=32+32=64
n=m/M => m=n*M=0,15*64=9,6 kg

64 kg SO₂...........32 kg O
9,6 kg SO₂.............t
t=(32*9,6):64=4,8 kg O

3)a)MH₂O=2+16=18
18 g H₂O.............2 g H
    a......................6 g H
a=(18*6):2=36 G H₂O

b)MPH₃=31+3=34
34 g PH₃..................3gH
    b..........................6 gH
b=(34*6):3=68 g PH₃

c)MH₂CO₃=2+12+48=62
62 g H₂CO₃.................2 g H
        c..........................6 g H
c=(62*6):2=186 g H₂CO₃