Răspuns :
ABC isoscel
AD _|_BC
AD= AB×AC/BC
AD=8×8/6
AD=32/3
A = AD×BC /2
A= 32/3×6/2
A=48 cm²
AD _|_BC
AD= AB×AC/BC
AD=8×8/6
AD=32/3
A = AD×BC /2
A= 32/3×6/2
A=48 cm²
ΔABC isocel
D mij [BC] ⇒ AD⊥BC
⇒ΔADB ,m(D)=90°
BD = DC = BC /2
BD = DC = 3
ΔADB ,m(D)=90°
AD²=8²-3²
AD²=64 -9
AD²=55
AD =√55
AΔABD= AD· BD /2
=√55 · 3 /2
=3√55/2 cm²
D mij [BC] ⇒ AD⊥BC
⇒ΔADB ,m(D)=90°
BD = DC = BC /2
BD = DC = 3
ΔADB ,m(D)=90°
AD²=8²-3²
AD²=64 -9
AD²=55
AD =√55
AΔABD= AD· BD /2
=√55 · 3 /2
=3√55/2 cm²