Răspuns :
BD=4 cm
CD = 16 cm
BC =BD+CD= 4+16=20 cm
In ∆ ABC dr =>T cat
AB²=BD×BC
AB²= 4×20
AB²= 80
AB=√80
AB=4√5 cm
In ∆ABC de =>T Cat
AC²=16×20
AC² =320
AC=√320
AC=8√5 cm
CD = 16 cm
BC =BD+CD= 4+16=20 cm
In ∆ ABC dr =>T cat
AB²=BD×BC
AB²= 4×20
AB²= 80
AB=√80
AB=4√5 cm
In ∆ABC de =>T Cat
AC²=16×20
AC² =320
AC=√320
AC=8√5 cm
ΔABC
m(∡A)=90°
BD=4 cm
CD=16 cm
AB=?
AC=?
--------------------------------
BC=BD+CD
BC=4+16=20 (cm)
Pentru a afla lungimile catetelor vom folosi teorema catetei.
AB²=BD×BC
AB²=4×20
AB²=80
AB=√80
AB=4√5 (cm)
AC²=CD×BC
AC²=16×20
AC²=320
AC=√320
AC=8√5 (cm)
m(∡A)=90°
BD=4 cm
CD=16 cm
AB=?
AC=?
--------------------------------
BC=BD+CD
BC=4+16=20 (cm)
Pentru a afla lungimile catetelor vom folosi teorema catetei.
AB²=BD×BC
AB²=4×20
AB²=80
AB=√80
AB=4√5 (cm)
AC²=CD×BC
AC²=16×20
AC²=320
AC=√320
AC=8√5 (cm)