Răspuns :
MCl2=35.5*2=71g/mol
MNH3=14+1*3=17g/mol
Maer=28.9g/mol
DCl2=MCl2/Maer=71/28.9=2.45
DNH3=MNH3/Maer=17/28.9=0.58
MNH3=14+1*3=17g/mol
Maer=28.9g/mol
DCl2=MCl2/Maer=71/28.9=2.45
DNH3=MNH3/Maer=17/28.9=0.58
in rezolvarea anterioara s-a calculat densitatea relativa
densitatea absoluta ,ro= M/Vm
la Cl2. ro=71g/mol / 22,4 l/mol= 3,17g/l
la NH3 ro= 17/22,4=>0,76 g/l
densitatea absoluta ,ro= M/Vm
la Cl2. ro=71g/mol / 22,4 l/mol= 3,17g/l
la NH3 ro= 17/22,4=>0,76 g/l