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Determinati masa solutiei de acid colrhodric cu concentratia 18,25% care neutralizeaza 108g solutia de hidroxid de potasiu cu concentratia 49%


Răspuns :

                                                                  Din sol. de KOH se calc. md de KOH
      X        52,92g
      HCl + KOH = KCl +H2O                       md=c.ms:100 =49.108 :100
   36,5g   56g                                                                     =52,92g KOH

x=36,5.52,92:56=34,49g HCl  ( md )              (  Punctul . inseamna inmultit)

Acum se calc. ms de HCl

ms=md.100:c

ms=34,49.100:18,25 =188,9 g sol.HCl