a moli CH2=CH-CH3.+a Br2----> a CH2Br-CHBr-CH3
b moli CH≡C-CH3..+2bBr2---> b CHBr2-CBr2-CH3
160(a+2b)= 48g brom---> a+2b= 0,3mol
b moli CH≡C-CH3 + b[Cu(NH3)]Cl---> bCuC≡C-CH3↓ + bNH3 + bHCl,
M,CuC3H3= 103g/mol
n(niu)=5,125g/103g/mol= 0,05mol-------> b=0,05mol propina
a= 0,3-0,05=> 0,25mol propena
M,propina= 40g/mol
M,propena= 42g/mol
m,amestec= 0,05x40+0,2x42=....................calculeaza
total 0,3mol........0,25mol propena........0,05mol propina
100mol.................x..........................y............................calculeaza x si y
