[tex]\displaystyle\\
B=\text{ baza mare}\\
b=\text{ baza mica}\\\\
\text{Rezolvare:}\\\\
\begin{cases}
\dfrac{B+b}{2}=25~~~~~\text{(linia mijlocie)}\\\\
\dfrac{B-b}{2} =6~~~~~\text{(distanta dintre mijloacele diagonalelor)}
\end{cases} \\\\\\
\begin{cases}
B+b=25 \times 2\\
B-b=6 \times 2
\end{cases} \\\\
\begin{cases}
B+b=50\\
B-b=12
\end{cases} \\
-------- \text{Adunam ecuatiile:}\\
2B~~~~/=62\\\\
B= \frac{62}{2}=\boxed{31~cm}\\
B+b=50\\
b = 50 - B=50-31=\boxed{19~cm}
[/tex]
